Same moles, same CO₂: marble, NaHCO₃ and Na₂CO₃ with HCl
Treat 5 mmol each of CaCO₃ (0.5 g), NaHCO₃ (0.42 g) and Na₂CO₃ (10 mL of 0.5 M) with excess HCl and show that all give the same amount of CO₂ (5 mmol).
About this experiment
| Subject | Chemistry |
|---|---|
| Class | 11 |
| Unit | 11. NEET / JEE Practice Labs (Class XI) |
| Level | NEET level |
| Access | Included in a PractiSci plan |
What you do in the lab
Change the controls and watch the chemistry behave in real time in 3D. Live readouts and graphs show the numbers behind it, and the Learn tab has the theory, procedure, observations and viva questions. Works on a phone or a laptop, in English and Hindi.
Topics: chemistry · NEET / JEE Practice Labs (Class XI)
More from this unit
- Ammonia–ammonium chloride: a basic buffer
- Common ion effect on ammonia: NH₄Cl suppresses its ionisation
- Diluting a strong and a weak acid ten-fold
- Heat of displacement: Mg, Zn and Fe in copper sulphate
- Why do some salts cool the water? Urea, KNO₃ and NaCl
- Freezing mixtures: ice vs ice–salt
- Gravimetric estimation of barium as BaCrO₄
- Gravimetric estimation of calcium as CaC₂O₄